A rectangular lite is 42 in. wide and 78 in. high. Glazing stop is needed around all four sides, and the cut list adds 10 percent waste. What stop length should be carried?
Correct Answer
D) 264 in.
Perimeter is 2 x (42 + 78) = 240 in. Adding 10 percent waste gives 240 x 1.10 = 264 in. Other choices omit one side, omit waste, or add too much allowance.
Why This Is the Correct Answer
Perimeter is 2 x (42 + 78) = 240 in. Adding 10 percent waste gives 240 x 1.10 = 264 in. Other choices omit one side, omit waste, or add too much allowance.
Why the Other Options Are Wrong
Option A: 220 in.
glazing stops, choice a: 220 in. implies about -8.33 percent added to 240; the stated add-on is 10 percent in.
Option B: 240 in.
glazing stops, choice b: 240 in. is an intermediate from the steps (Perimeter is 2 x (42 + 78) = 240 in.); the calculation continues to 264 in.
Option C: 280 in.
glazing stops, choice d: 280 in. implies about 16.67 percent added to 240; the stated add-on is 10 percent in.
Memory Technique
Store glazing stops with its last math move; nearby answers are usually unfinished versions of 264 in.
Reference Hint
Open Principles and Practices of Commercial Construction, 11th Ed., 2024; use the index entry or section for "Glazing stop cut length takeoff" to confirm that Perimeter is 2 x (42 + 78) = 240 in.
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