An anchored veneer elevation is 36 ft long and 14 ft high. Using the prescriptive maximum of 2.67 sq ft per anchor, what minimum number of veneer anchors is required before adding opening-edge anchors?
Correct Answer
A) 189 anchors
Area is 36 x 14 = 504 sf. Divide by 2.67 sf per anchor: 504/2.67 = 188.76, so at least 189 anchors are needed. Other choices result from rounding down, using about 3 sf per anchor, or adding an arbitrary allowance not requested.
Why This Is the Correct Answer
Area is 36 x 14 = 504 sf. Divide by 2.67 sf per anchor: 504/2.67 = 188.76, so at least 189 anchors are needed. Other choices result from rounding down, using about 3 sf per anchor, or adding an arbitrary allowance not requested.
Why the Other Options Are Wrong
Option B: 172 anchors
veneer anchors, choice a: 172 anchors backs into 0.91 when divided by 189; the accepted setup gives 1 on that same base.
Option C: 176 anchors
veneer anchors, choice c: 176 anchors omits a required add-on/subtraction; the numeric gap is 13.
Option D: 200 anchors
veneer anchors, choice d: 200 anchors adds an extra unstated add-on/subtraction; the numeric gap is 11.
Memory Technique
Say the veneer anchors rule aloud as a chain; the chain ends at 189 anchors, not an intermediate stop.
Reference Hint
Open International Building Code 2021 or 2024; use IBC anchored masonry veneer area per anchor to confirm that Area is 36 x 14 = 504 sf.
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