A straight 32 ft partition has studs at 16 in. on center, with a stud at each end and no openings. What stud count should be carried for the run?
Correct Answer
C) 25 studs
The run is 32 x 12 = 384 in. At 16 in. spacing, 384/16 = 24 spaces; with studs at both ends, count spaces plus one, so 25 studs. Other choices omit an end stud, add an extra bay, or use a shorter spacing.
Why This Is the Correct Answer
The run is 32 x 12 = 384 in. At 16 in. spacing, 384/16 = 24 spaces; with studs at both ends, count spaces plus one, so 25 studs. Other choices omit an end stud, add an extra bay, or use a shorter spacing.
Why the Other Options Are Wrong
Option A: 24 studs
stud layout, choice a: the answer choice lifts 24 studs from the working line spacing, 384/16 = 24 spaces.
Option B: 26 studs
stud layout, choice c: 26 studs is wrong because 26 studs adds one stud beyond the two-end layout; 84 spaces plus the far-end stud gives 85, not 86.
Option D: 28 studs
stud layout, choice d: 28 studs assumes a spacing/count different from 12 in. on center with studs at both ends; the accepted count is 84 spaces + 1 end stud = 85.
Memory Technique
Keep a panel space beside stud layout: if one number is skipped, the option drifts away from 25 studs.
Reference Hint
Open Carpentry and Building Construction, 2016; use the index entry or section for "Wall framing layout at regular stud spacing" to confirm that The run is 32 x 12 = 384 in.
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