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Sale prices are $200,000, $220,000, $240,000. Treat these as a sample and divide the squared-deviation sum by n−1 when computing the standard deviation. Report to the nearest dollar.

Correct Answer

B) $20,000

Mean=$220,000; Σ(x−mean)²=800000000. Standard deviation=√[800000000/2]=20000, rounded to $20,000. Variance and the data range are different quantities.

Answer Options
A
$16,330
B
$20,000
C
$40,000
D
$220,000

Why This Is the Correct Answer

Option B is correct because the mean is $220,000, the deviations are −20,000, 0 and +20,000, and their squares sum to 800,000,000. Dividing by n − 1 = 2 gives a variance of 400,000,000, and the square root is $20,000.

Why the Other Options Are Wrong

Option A: $16,330

Option A, $16,330, is the population standard deviation, which divides by n = 3 instead of n − 1: √(800,000,000 / 3) = √266,666,667 ≈ $16,330. The question asks for the sample version, √(800,000,000 / 2) = $20,000.

Option C: $40,000

Option C, $40,000, is the range, $240,000 − $200,000. The sample standard deviation is √(800,000,000 / 2) = $20,000.

Option D: $220,000

Option D, $220,000, is the mean of the three prices, a measure of center. The sample standard deviation is √(800,000,000 / 2) = $20,000.

Square, sum, divide, root

Find each deviation from the mean, square it, sum the squares, divide by n − 1 for a sample, then take the square root.

How to use: Use this sequence to work any sample standard deviation problem step by step.

Exam Tip

Check whether the question says sample (n − 1) or population (n); both answers often appear as options.

Common Mistakes to Avoid

  • -Dividing by n instead of n − 1 for a sample
  • -Forgetting to take the square root and reporting the variance
  • -Confusing the range with the standard deviation

Concept Deep Dive

Analysis

This question tests calculating a sample standard deviation with the n − 1 divisor. The mean of $200,000, $220,000 and $240,000 is $220,000, and the squared deviations sum to 800,000,000. Dividing by n − 1 = 2 gives 400,000,000, and its square root is $20,000.

Background Knowledge

The sample standard deviation subtracts the mean from each value, squares the results, adds the squares, divides by the sample size less one and takes the square root. Dividing by n − 1 instead of n gives a slightly larger result for a sample. Variance and range are different quantities from standard deviation.

Real-World Application

An appraiser treats three adjusted comparable prices as a sample and finds a standard deviation of $20,000. That spread around the $220,000 mean tells the appraiser how much the indications disagree before final reconciliation.

sample standard deviationn minus 1variancedispersion
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