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Given first quartile $400,000, median $440,000 and third quartile $500,000, compute the trimean (Q1+2×median+Q3)/4. Report to the nearest dollar.

Correct Answer

A) $445,000

(400000+2×440000+500000)/4=445000. The median receives twice the weight of either quartile.

Answer Options
A
$445,000
B
$446,667
C
$450,000
D
$440,000

Why This Is the Correct Answer

Option A is correct because (400,000 + 2 × 440,000 + 500,000) ÷ 4 = (400,000 + 880,000 + 500,000) ÷ 4 = 1,780,000 ÷ 4 = $445,000. The median receives twice the weight of either quartile. Dividing by 4 reflects the total weight of one plus two plus one.

Why the Other Options Are Wrong

Option B: $446,667

Option B, $446,667, comes from giving all three values equal weight: (400,000 + 440,000 + 500,000) ÷ 3 ≈ $446,667. The trimean doubles the median: 1,780,000 ÷ 4 = $445,000.

Option C: $450,000

Option C, $450,000, is the average of the two quartiles, (400,000 + 500,000) ÷ 2, which ignores the median entirely. The trimean is (400,000 + 880,000 + 500,000) ÷ 4 = $445,000.

Option D: $440,000

Option D, $440,000, is the median alone without including the quartiles. The trimean is (400,000 + 2 × 440,000 + 500,000) ÷ 4 = $445,000.

One, two, one over four

Weight Q1 once, the median twice, Q3 once, then divide by the total weight of four.

How to use: Use this whenever a question asks for a trimean from quartiles and the median.

Exam Tip

If you divide by 3, you have forgotten that the median counts twice; the divisor is 4.

Common Mistakes to Avoid

  • -Weighting the median only once and dividing by 3
  • -Averaging only the two quartiles
  • -Reporting the median as the trimean

Concept Deep Dive

Analysis

This question tests applying the trimean formula, (Q1 + 2 × median + Q3) ÷ 4. The median is weighted twice, so the total weight is four. The distractors come from equal weighting, ignoring the median, or reporting the median alone.

Background Knowledge

The trimean is a resistant measure of central tendency that blends the median with the first and third quartiles. Because it uses quartiles rather than extreme values, it is less influenced by outliers than the mean. It reflects some information about skewness that the median alone does not.

Real-World Application

An analyst summarizing a skewed price distribution reports the trimean alongside the median. Because Q3 sits farther above the median than Q1 sits below it, the trimean comes out slightly above the median, reflecting the upward skew.

trimeanquartilesmedianresistant measurecentral tendency
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