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Sales ComparisonEASY16.4% of exam

Two verified otherwise identical cash-equivalent sales differ only in finishing 1,200 square feet of basement. They sold for $432,000 finished and $408,000 unfinished in a stable market. What per-square-foot finish contribution does the pair indicate? A subject has 1,000 square feet, but no transfer or adjustment amount is requested.

Correct Answer

B) 20.00

(432000 − 408000) / 1200 = 20 per square foot; the subject’s 1000 square feet is not the denominator. Common errors: dividing by the subject’s 1,000 square feet instead of the pair’s 1,200 gives 24.00; dividing the finished sale price by the area gives 360.00; dividing by both areas gives 10.91.

Answer Options
A
10.91
B
20.00
C
24.00
D
360.00

Why This Is the Correct Answer

Option B is correct because ($432,000 - $408,000) / 1,200 = $24,000 / 1,200 = 20.00 per square foot. The pair differs only in the 1,200 square feet of basement finish, so that area is the correct denominator. The subject's 1,000 square feet would matter only when applying the rate, which the question does not ask for.

Why the Other Options Are Wrong

Option A: 10.91

Option A is wrong because 10.91 comes from 24,000 / (1,200 + 1,000) = 24,000 / 2,200, dividing by both areas combined. The rate comes from the pair alone: 24,000 / 1,200 = 20.00.

Option C: 24.00

Option C is wrong because 24.00 comes from 24,000 / 1,000, dividing by the subject's 1,000 square feet instead of the pair's 1,200. The correct rate is 24,000 / 1,200 = 20.00.

Option D: 360.00

Option D is wrong because 360.00 comes from 432,000 / 1,200, dividing the finished sale price by the finished area. The contribution comes from the price difference: (432,000 - 408,000) / 1,200 = 20.00.

Pair's gap over pair's area

Take the price gap between the two sales and divide it by the area that differs between those same two sales. The subject waits until you apply the rate.

How to use: Use this rule when a paired-sales problem includes extra subject data that is not part of the rate calculation.

Exam Tip

Identify which figures belong to the pair and which belong to the subject before calculating. Questions often add subject data as a distractor.

Common Mistakes to Avoid

  • -Dividing the price difference by the subject's area
  • -Dividing a full sale price by the area instead of the price difference
  • -Combining the pair's and subject's areas in the denominator

Concept Deep Dive

Analysis

This question tests extracting a per-square-foot rate from a paired sale. The price difference between the finished and unfinished basement sales is divided by the 1,200 square feet of finish in the pair. The subject's 1,000 square feet is a distractor because no adjustment for the subject is requested.

Background Knowledge

Paired sales can support adjustment rates by isolating the price effect of a single difference. The rate is derived from the characteristics of the paired sales themselves, and only then applied to the difference between each comparable and the subject.

Real-World Application

An appraiser finds two nearly identical homes in a stable subdivision, one with a finished basement and one without. The appraiser divides the price difference by the finished area to get a per-square-foot rate, then later applies it to each comparable's basement-finish difference from the subject.

paired salesbasement finishprice per square footadjustment ratecontribution
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