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Cost ApproachMEDIUM13.6% of exam

Dwelling 2,400 sf costs $128/sf and a separate 480 sf garage $46/sf. No cost item overlaps and land is excluded. What total cost new results?

Correct Answer

C) $329,280

2400×128+480×46 = 329280. Common errors: leaving out the garage gives $307,200; pricing the garage at the dwelling rate gives $368,640; pricing the dwelling at the garage rate gives $132,480.

Answer Options
A
$132,480
B
$307,200
C
$329,280
D
$368,640

Why This Is the Correct Answer

Option C is correct because the dwelling costs 2,400 × $128 = $307,200 and the garage costs 480 × $46 = $22,080, for a total of $307,200 + $22,080 = $329,280. The square foot method applies each rate to the area it fits.

Why the Other Options Are Wrong

Option A: $132,480

Option A is wrong because $132,480 is (2,400 + 480) × $46, pricing the dwelling at the garage rate. The dwelling uses $128 per square foot, giving a total of $329,280.

Option B: $307,200

Option B is wrong because $307,200 is 2,400 × $128, the dwelling alone, leaving out the $22,080 garage. Adding the garage gives $329,280.

Option D: $368,640

Option D is wrong because $368,640 is (2,400 + 480) × $128, pricing the garage at the dwelling rate. The garage uses $46 per square foot, giving $307,200 + $22,080 = $329,280.

Match rate to room

Living area gets the living rate and the garage gets the garage rate. Multiply each, then add.

How to use: Use this check to avoid applying one rate to all areas in a cost problem.

Exam Tip

Write out each area times its rate on scratch paper before adding; the wrong options usually blend or drop a component.

Common Mistakes to Avoid

  • -Pricing the whole building at the garage rate
  • -Pricing the garage at the living-area rate
  • -Forgetting to add the garage

Concept Deep Dive

Analysis

This question tests applying separate square foot rates to the dwelling and the garage. Each area is multiplied by its own rate, and the two results are added. Using one rate for both areas or dropping one area produces the distractors.

Background Knowledge

The square foot method applies a cost per square foot to the measured area of the improvement. Different components such as finished living area and garages are usually priced at different rates because their construction differs. All relevant direct and indirect costs should be captured without overlap.

Real-World Application

An appraiser uses a cost manual to price a ranch home's 2,400 square feet of living area at one rate and its 480-square-foot garage at a lower rate. The combined figure becomes the improvement cost new in the cost approach.

square foot methodcost newgarageunit costliving area
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