6 questions · 13% of the Calculations exam
Why B is correct
The question supplies the applicable factor, so multiply 50 amperes by 0.70 to obtain 35 amperes. Dividing by the factor or subtracting 70 as a raw number misuses the percentage.
Why C is correct
EV charging is treated as continuous in this case. Multiplying the 40-ampere maximum load by 125 percent gives a required branch-circuit ampacity of 50 amperes.
Why D is correct
Where the code permits omission of a noncoincident load, carry the larger of the two loads that cannot operate simultaneously. The larger value is 72 amperes; adding or averaging would ignore the stated permission.
Why B is correct
Reverse the continuous-load factor: 60 ÷ 1.25 = 48 amperes maximum continuous EV input. Keep units consistent and use only the factors stated; no optional method or unstated demand factor is assumed.
Why C is correct
The applicable demand load is 160 × 0.75 = 120 amperes. The factor applies only because the question explicitly supplies it for this step.
Why D is correct
Reverse the supplied factor: 42 ÷ 0.60 = 70 amperes rated primary current. Keep units consistent and use only the factors stated; no optional method or unstated demand factor is assumed.
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