A veneer shelf angle run needs 96 ft of flashing. The crew expects eight field splices, each with a 6 in. lap. What total flashing length should be supplied?
Correct Answer
C) 100 ft
Eight laps at 6 in. each add 48 in., or 4 ft. Total flashing length is 96 + 4 = 100 ft. Other choices: 98 ft uses only four laps, 104 ft assumes 12 in. laps, and 108 ft doubles the lap allowance.
Why This Is the Correct Answer
Eight laps at 6 in. each add 48 in., or 4 ft. Total flashing length is 96 + 4 = 100 ft.
Why the Other Options Are Wrong
Option A: 98 ft
flashing quantity, choice a: 98 ft omits a required add-on/subtraction; the numeric gap is 2.
Option B: 104 ft
flashing quantity, choice c: 104 ft is off by 4 from the checked result 100 ft because it misuses the 4 item (at 6 in).
Option D: 108 ft
flashing quantity, choice d: 108 ft adds an extra unstated add-on/subtraction; the numeric gap is 8.
Memory Technique
Remember flashing quantity as "base, adjustment, final unit"; the last unit should read 100 ft.
Reference Hint
Open Principles and Practices of Commercial Construction, 11th Ed., 2024; use the index entry or section for "Masonry flashing takeoff" to confirm that Eight laps at 6 in.
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