A foundation plan shows a footing detail with dimensions 3'-0" x 3'-0" x 1'-6" supporting a 12" x 12" column. What is the bearing pressure if the total load is 45,000 pounds?
Correct Answer
B) 5,000 psf
Bearing pressure = Total load ÷ Footing area. Area = 3' × 3' = 9 sq ft. Pressure = 45,000 lbs ÷ 9 sq ft = 5,000 psf.
Why This Is the Correct Answer
Bearing pressure = Total load ÷ Footing area. Area = 3' × 3' = 9 sq ft. Pressure = 45,000 lbs ÷ 9 sq ft = 5,000 psf.
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