A contractor discovers that the soil bearing capacity at a job site is 1,500 psf. The house will impose a total load of 45,000 pounds on a continuous footing. What is the minimum footing width required?
Correct Answer
D) 30 inches
Required footing area = 45,000 lbs ÷ 1,500 psf = 30 sq ft per linear foot, so 30 inches wide minimum.
Why This Is the Correct Answer
The calculation: Required footing area = Total load ÷ Soil bearing capacity = 45,000 lbs ÷ 1,500 psf = 30 square feet. For a continuous footing, this equals 30 inches of width per linear foot (since 30 sq ft per linear foot expressed as inches = 30 inches). The minimum footing width is 30 inches.
Why the Other Options Are Wrong
Option A: 42 inches
42 inches would result in an area of 42 sq ft per linear foot, far exceeding the 30 sq ft needed. This over-engineers the footing and is not the minimum required width.
Option B: 36 inches
36 inches provides 36 sq ft per linear foot of support capacity, which exceeds the 30 sq ft minimum. It is a valid width but not the minimum — the exam asks for the minimum.
Option C: 24 inches
24 inches would provide only 24 sq ft per linear foot of bearing area (24 in = 2 ft; 2 ft × 1,500 psf = 3,000 lbs/ft), which is insufficient. The footing would be undersized and could fail under the imposed load.
Memory Technique
Formula: Width (ft) = Load (lbs) ÷ Bearing Capacity (psf). Then convert feet to inches (× 12). Here: 45,000 ÷ 1,500 = 30 ft² per lineal foot → 30 inches wide. The numbers work out cleanly — 30 feet squared equals 30 inches because 30 ft² ÷ 1 linear ft = 30 ft = 30 inches.
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