A dewatering pump removes 24 gallons per minute for 27 minutes. How many gallons are removed?
Correct Answer
A) 648 gallons.
Flow volume is rate times time: 24 gallons per minute for 27 minutes equals 648 gallons.
Why This Is the Correct Answer
Flow volume is rate times time: 24 gallons per minute for 27 minutes equals 648 gallons.
Why the Other Options Are Wrong
Option B: 612 gallons total.
612 gallons total. is below the supported result for plumbing flow calculation; it likely omits allowance, conversion, coverage, or final round-up.
Option C: 672 gallons total.
672 gallons total. is above the supported result for plumbing flow calculation; it likely double-counts allowance, uses the wrong unit, or rounds too early.
Option D: 720 gallons total.
720 gallons total. is above the supported result for plumbing flow calculation; it likely double-counts allowance, uses the wrong unit, or rounds too early.
Memory Technique
Plumbing Flow cart for Estimating Temporary: volume first, rate second, whole the controlling choice last.
Reference Hint
Study anchor (closed-book): memorize Plumbing flow calculation from California Plumbing Code, California Code of Regulations Title 24. / Title 24 California Plumbing Code pump capacity concepts; know the rule or calculation trigger without relying on exam-room lookup.
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