A balanced 480-volt three-phase load draws 35 amperes at 0.85 power factor. Using 1.732, approximately how much real power does it use?

Where to look it up

Explicit exercise assumptions; not a universal code requirement.

Why A is correct

For a balanced three-phase load, real power is 1.732 × line-to-line RMS voltage × RMS line current × power factor. Here, 1.732 × 480 × 35 × 0.85 = 24,732.96 watts, or about 24.7 kW.