For a supplied proportional-area exercise, increase a 6,530 circular-mil conductor by the exact ratio 16,510/6,530. The supplied size list is 12 AWG = 6,530, 10 AWG = 10,380, 8 AWG = 16,510 and 6 AWG = 26,240 circular mils. Which listed size equals the result?
- A12 AWG copper
- B10 AWG copper
- C6 AWG copper
- 8 AWG copper
Where to look it up
Explicit exercise assumptions; not a universal code requirement.
Why D is correct
6,530 × (16,510 / 6,530) = 16,510 circular mils exactly. Do not round the ratio to 2.53 before selecting the size. This is the stated proportional-area exercise, not a universal grounding-conductor rule.