A project has activities with the following durations: A(5 days), B(3 days), C(7 days), D(4 days). Path 1: A-B-D = 12 days, Path 2: A-C-D = 16 days. What is the total float for activities on Path 1?
Correct Answer
C) 4 days
Total float is the difference between the critical path duration and the path duration. Path 2 (16 days) is critical, so Path 1 has 16-12 = 4 days of total float.
Why This Is the Correct Answer
Total float represents the amount of time an activity or path can be delayed without affecting the project completion date. The critical path is the longest path through the network, which is Path 2 at 16 days. Path 1 takes 12 days, so it has 16 - 12 = 4 days of total float. This means activities on Path 1 can be delayed up to 4 days without impacting the overall project duration.
Why the Other Options Are Wrong
Option A: 8 days
8 days would be incorrect as it suggests Path 1 has more float than actually exists. This might result from incorrectly calculating the difference or misidentifying which path is critical. The actual float is only 4 days.
Option B: 2 days
2 days is too small and doesn't represent the correct calculation. This might result from subtracting in the wrong direction or making an arithmetic error in the float calculation.
Option D: 0 days
0 days would indicate that Path 1 is also critical, which is incorrect. Only the longest path (Path 2 at 16 days) is critical. Path 1 has slack time available.
Memory Technique
Remember 'FLOAT = CRITICAL - CURRENT': Total float equals the critical path duration minus the current path duration. The longest path floats nothing, shorter paths float the difference.
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