A project has activities with the following durations: A=5 days, B=8 days, C=6 days, D=4 days. Path 1: A-C (11 days), Path 2: B-D (12 days). What is the total float for Path 1?
Correct Answer
B) 1 day
Path 2 (12 days) is the critical path. Path 1 has a total duration of 11 days, so its total float is 12-11 = 1 day.
Why This Is the Correct Answer
Total float represents the amount of time an activity or path can be delayed without affecting the project completion date. To calculate total float for a path, you subtract the path duration from the critical path duration. Since Path 2 (B-D) has the longest duration at 12 days, it becomes the critical path. Path 1 (A-C) has 11 days duration, so its total float is 12 - 11 = 1 day.
Why the Other Options Are Wrong
Option A: 0 days
0 days would indicate that Path 1 is also a critical path with no float time available, but Path 1 only takes 11 days compared to the 12-day critical path.
Option C: 2 days
2 days would result from incorrectly calculating the difference, possibly by using wrong path durations or misidentifying the critical path.
Option D: 3 days
3 days significantly overestimates the float time and would result from major calculation errors in either path duration or critical path identification.
Memory Technique
Remember 'Float = Critical minus Current' - the float time equals the critical path duration minus the current path duration.
Reference Hint
Look up 'Critical Path Method (CPM)' and 'Float Calculations' in project management or scheduling chapters of construction management references.
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