A project has activities A (5 days), B (8 days), C (6 days), and D (4 days). Activity B can start after A is complete, C can start after A is complete, and D can start after both B and C are complete. What is the critical path duration?
Correct Answer
A) 17 days
The critical path is A-B-D (5+8+4=17 days). Path A-C-D takes 15 days (5+6+4), making A-B-D the longest path and therefore the critical path.
Why This Is the Correct Answer
The critical path is the longest sequence of activities from start to finish. To find it, we must calculate all possible paths through the network. Path A-B-D takes 5+8+4=17 days, while path A-C-D takes 5+6+4=15 days. Since A-B-D is longer at 17 days, it becomes the critical path that determines the minimum project duration.
Why the Other Options Are Wrong
Option B: 23 days
15 days represents the duration of path A-C-D (5+6+4=15), which is the shorter path and therefore not the critical path.
Option D: 19 days
23 days would only be possible if activities were done sequentially (5+8+6+4=23), but the network shows B and C can run in parallel after A, so this ignores the parallel scheduling advantage.
Memory Technique
Remember 'Longest = Critical' - the critical path is always the LONGEST path through the network, not the shortest or most activities.
Reference Hint
Project Management chapter, specifically Critical Path Method (CPM) and network scheduling sections
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