A drywall contractor needs to finish 2,400 square feet of drywall. If one worker can tape and finish 300 square feet per day, how many worker-days are required?
Correct Answer
D) 8 worker-days
Total area ÷ productivity rate = 2,400 sq ft ÷ 300 sq ft per day = 8 worker-days. This calculation assumes consistent productivity and includes all finishing operations (taping, mudding, and sanding).
Why This Is the Correct Answer
Option B is correct because this is a straightforward division problem using the basic productivity formula. When you divide the total work (2,400 sq ft) by the worker's daily productivity rate (300 sq ft per day), you get exactly 8 worker-days. This calculation assumes one worker working at a consistent rate and includes all phases of drywall finishing work.
Why the Other Options Are Wrong
Option B: 6 worker-days
Option D significantly overestimates the time required. 12 worker-days would complete 3,600 sq ft (12 × 300 = 3,600), which is 1,200 sq ft more than needed.
Option C: 10 worker-days
Option A underestimates the time required. 6 worker-days would only complete 1,800 sq ft (6 × 300 = 1,800), leaving 600 sq ft unfinished.
Memory Technique
Remember 'TPT' - Total ÷ Productivity = Time. Also, 2,400 ÷ 300 is the same as 24 ÷ 3 = 8, making the math easier to visualize.
Reference Hint
Look up labor productivity rates and scheduling calculations in construction management or estimating chapters of your contractor reference manual.
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